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Lim_(X->0) ("Sec"^"X" - "Log" (1 + X))/"X"^2 is Equal To:

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Question

`lim_(x->0) ("sec"^"x" - "log" (1 + x))/"x"^2` is equal to:

Options

  • `1/2`

  • `1/3`

  • `3/2`

  • `2/3`

MCQ
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Solution

`3/2`

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Logarithm and Function (Entrance Exam)
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