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Lim N → ∞ 2 N − 1 Sin ( a 2 N ) - Mathematics

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Question

\[\lim_{n \to \infty} 2^{n - 1} \sin \left( \frac{a}{2^n} \right)\] 

 

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Solution

\[\lim_{n \to \infty} 2^{n - 1} \sin \left( \frac{a}{2^n} \right)\]
\[ = \lim_{n \to \infty} \frac{2^n}{2} \times \frac{\sin \left( \frac{a}{2^n} \right)}{\left( \frac{a}{2^n} \right)} \times \left( \frac{a}{2^n} \right)\]
\[Let y = \frac{a}{2^n}\]
\[If n \to \infty , then   y \to 0 . \]
\[ = \lim_{y \to 0} \frac{a}{2} \times \left( \frac{\sin y}{y} \right)\]
\[ \Rightarrow \frac{a}{2}\] 

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Chapter 29: Limits - Exercise 29.8 [Page 62]

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RD Sharma Mathematics [English] Class 11
Chapter 29 Limits
Exercise 29.8 | Q 25 | Page 62

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