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Let X be a discrete random variable. The probability distribution of X is given below: X 30 10 –10 P(X) 1/5 3/10 1/2 Then E(X) will be: - Mathematics

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Question

Let X be a discrete random variable. The probability distribution of X is given below:

X 30 10 –10
P(X) `1/5` `3/10` `1/2`

Then E(X) will be:

Options

  • 1

  • 4

  • 2

  • 30

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Solution

4

Explanation:

E(X) = ΣX · P(X)

= `30 xx 1/5 + 10 xx 3/10 - 10 xx 1/2`

= 6 + 3 – 5

= 4

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