Question

Let l be the lower class limit of a class-interval in a frequency distribution and m be the mid point of the class. Then, the upper class limit of the class is

Options

•  m+ \[\frac{l + m}{2}\]

   

•  l+ \[\frac{m + l}{2}\]

   

• 2m − 1

• m − 2l

Answer 1

Given that, the lower class limit of a class-interval is l and the mid-point of the class is m. Let u be the upper class limit of the class-interval. Therefore, we have

`m = (l+u) /2`

⇒ l +u = 2m

⇒ u = 2m - 1

Thus the upper class limit of the class is (2m - l) .