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Question
Let a vector `veca` be coplanar with vectors `vecb = 2hati + hatj + hatk` and `vecc = hati - hatj + hatk`. If `veca` is perpendicular to `vecd = 3hati + 2hatj + 6hatk` and `|veca| = sqrt(10)`. Then a possible value of `[(veca, vecb, vecc)] + [(veca, vecb, vecd)] + [(veca, vecc, vecd)]` is equal to ______.
Options
–42
–40
–29
–38
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Solution
Let a vector `veca` be coplanar with vectors `vecb = 2hati + hatj + hatk` and `vecc = hati - hatj + hatk`. If `veca` is perpendicular to `vecd = 3hati + 2hatj + 6hatk` and `|veca| = sqrt(10)`. Then a possible value of `[(veca, vecb, vecc)] + [(veca, vecb, vecd)] + [(veca, vecc, vecd)]` is equal to –42.
Explanation:
Let `veca = xhati + yhatj + zhatk`
Since `veca, vecb` and `vecc` are coplanar
∴ `[(veca, vecb, vecc)] = |(x, y, z),(2, 1, 1),(1, -1, 1)|` = 0
`\implies` 2x – y – 3z = 0 ...(i)
and `veca . vecd` = 0
3x + 2y + 6z = 0 ...(ii)
From (i) and (ii)
`x/|(-1, -3),(2, 6)| = (-y)/|(2, -3),(3, 6)| = z/|(2, -1),(3, 2)|` = λ
`\implies` x = 0, y = –21λ, z = 7λ
Given x2 + y2 + z2 = 10
441λ2 + 49λ2 = 10
λ2 = `1/49`
`\implies` λ = `±1/7`
∴ `veca = -3hatj + hatk` or `veca = 3hatj - hatk`
Now, `[(veca, vecb, vecc)] + [(veca, vecb, vecd)] + [(veca, vecc, vecd)] = [vecavecb + veccvecd]`
= `|(0, -3, 1),(3, 0, 2),(3, 2, 6)|` or `|(0, 3, -1),(3, 0, 2),(3, 2, 6)|`
= 42 or –42
