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Let `A=[[1,1,1],[3,3,3]],B=[[3,1],[5,2],[-2,1]]` and `C=[[4,2],[-3,2],[5,0]]`Verify That Ab = Ac Though B ≠ C, A ≠ O. - Mathematics

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Question

Let `A=[[1,1,1],[3,3,3]],B=[[3,1],[5,2],[-2,4]]` and `C=[[4,2],[-3,5],[5,0]]`Verify that AB = AC though B ≠ CA ≠ O.

 
Sum
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Solution

\[Here, \]

\[A = \begin{bmatrix}1 & 1 & 1 \\ 3 & 3 & 3\end{bmatrix}, B = \begin{bmatrix}3 & 1 \\ 5 & 2 \\ - 2 & 4\end{bmatrix} \text{and C} = \begin{bmatrix}4 & 2 \\ - 3 & 5 \\ 5 & 0\end{bmatrix}\]

\[Now, \]

\[AB = \begin{bmatrix}1 & 1 & 1 \\ 3 & 3 & 3\end{bmatrix}\begin{bmatrix}3 & 1 \\ 5 & 2 \\ - 2 & 4\end{bmatrix}\]

\[ \Rightarrow AB = \begin{bmatrix}3 + 5 - 2 & 1 + 2 + 4 \\ 9 + 15 - 6 & 3 + 6 + 12\end{bmatrix}\]

\[ \Rightarrow AB = \begin{bmatrix}6 & 7 \\ 18 & 21\end{bmatrix}\]

\[\]

\[AC = \begin{bmatrix}1 & 1 & 1 \\ 3 & 3 & 3\end{bmatrix}\begin{bmatrix}4 & 2 \\ - 3 & 5 \\ 5 & 0\end{bmatrix}\]

\[ \Rightarrow AC = \begin{bmatrix}4 - 3 + 5 & 2 + 5 + 0 \\ 12 - 9 + 15 & 6 + 15 + 0\end{bmatrix}\]

\[ \Rightarrow AC = \begin{bmatrix}6 & 7 \\ 18 & 21\end{bmatrix}\]

So, AB = AC though B ≠ C , A ≠ O.

 
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Chapter 5: Algebra of Matrices - Exercise 5.3 [Page 46]

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RD Sharma Mathematics [English] Class 12
Chapter 5 Algebra of Matrices
Exercise 5.3 | Q 70 | Page 46
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