Question

Length of the second’s pendulum is 100 cm. Find the length of another pendulum whose time period is 2.4 s.

Answer 1

We know the time period of the second’s pendulum is 2 s.

∴ T₁ = 2 s, l₁ = 100 cm

T₂ = 2.4 s, l₂ = ?

`"T"_1/"T"_2=sqrt("l"_1/"l"_2)`

`2/2.4=sqrt(100/"l"_2)`

`1/1.2=sqrt(100/"l"_2)`

Squaring both sides,

`1/1.44=100/"l"_2`

l₂ = 100 × 1.44 = 144 cm