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Knowing that the value of K for [Cu(NH3)4]2+ is 4.5 × 10^11 and for [Cu(CN)4]2− is 2.0 × 10^27, suggest which complex species will furnish less Cu2+ ions in solution. - Chemistry (Theory)

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Question

Knowing that the value of K for [Cu(NH3)4]2+ is 4.5 × 1011 and for [Cu(CN)4]2− is 2.0 × 1027, suggest which complex species will furnish less Cu2+ ions in solution.

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Solution

The stability constant (K) represents the equilibrium constant for the complex’s formation from its metal ions and ligands. A higher K value indicates a more stable complex, which means it is less likely to dissociate and release free Cu2+ ions into the solution.

For [Cu(NH3)4]2+, the stability constant K = 4.5×1011

For [Cu(CN)4]2−, the stability constant K = 2.0 × 1027

Since [Cu(CN)4]2− has a significantly higher K value, it is much more stable compared to [Cu(NH3)4]2+. This means [Cu(CN)4]2− will furnish fewer Cu2+ions in solution because it is less likely to dissociate and release Cu2+ ions.

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Chapter 9: Coordination Compounds - Review Exercises [Page 541]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 9 Coordination Compounds
Review Exercises | Q 9.63 (ii) (a) | Page 541
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