Advertisements
Advertisements
Question
Kantabai bought \[1\frac{1}{2}\] kg tea and 5 kg sugar from a shop. She paid ₹ 50 as return fare for rickshaw. Total expense was ₹ 700. Then she realised that by ordering online the goods can be bought with free home delivery at the same price. So next month she placed the order online for 2 kg tea and 7 kg sugar. She paid ₹ 880 for that. Find the rate of sugar and tea per kg.
Advertisements
Solution
Let the rate of tea be x ₹ per kg, and that of sugar be y ₹ per kg.
When Kantabai bought the items by going to the shop,
\[\frac{3}{2}x + 5y + 50 = 700\]
`3/2x + 5y = 700 - 50`
`3/2x xx 2 + 5y xx 2= 650 xx 2`
3x + 10y = 1300 ...(I)
When Kantabai bought the items online, then
2x + 7y = 880 ...(II)
Multiplying (I) with 2 and (II) with 3, we get
6x + 20y = 2600 ...(III)
6x + 21y = 2640 ...(IV)
(IV) - (III)
y = 40
Putting the value of y = 40 in (II)
3x + 10 × 40 = 1300
3x + 400 = 1300
3x = 1300 - 400
x = `900/3`
∴ x = 300
Thus, tea is 300 ₹ per kg, and sugar is 40 ₹ per kg.
