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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Jupiter is at a distance of 824.7 million km from the Earth. Its angular diameter is measured to be 35.72˝. Calculate the diameter of Jupiter. - Physics

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Question

Jupiter is at a distance of 824.7 million km from the Earth. Its angular diameter is measured to be 35.72˝. Calculate the diameter of Jupiter.

Sum
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Solution

Given,

Given Distance of Jupiter = 824.7 × 106 km = 8.247 × 1011 m

angular diameter = 35.72 × 4.85 × 10-6rad = 173.242 × 10-6 rad
= 1.73 × 10-4 rad

∴ Diameter of Jupiter D = D × d = 1.73 × 10-4 rad × 8.247 × 1011 m

= 14.267 × 1o7 m = 1.427 × 108 m (or) 1.427 × `10^{5<"/""sup km"}`

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Chapter 1: Nature of Physical World and Measurement - Evaluation [Page 39]

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Samacheer Kalvi Physics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 1 Nature of Physical World and Measurement
Evaluation | Q IV. 4. | Page 39

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