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Question
Insert an irrational number between the following:
4 and 5
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Solution
Given: `sqrt(20)` is an irrational number between 4 and 5.
Step-wise calculation:
1. Evaluate the squares of the boundary numbers: 42 = 16, 52 = 25.
2. Since 20 is between 16 and 25: 16 < 20 < 25.
Taking square roots preserves order because the function `f(x) = sqrt(x)` is increasing for x > 0.
So, `4 = sqrt(16) < sqrt(20) < sqrt(25) = 5`.
3. `sqrt(20)` is irrational because 20 is not a perfect square no integer squared equals 20.
Hence, `sqrt(20)` cannot be expressed as a ratio of two integers.
The number `sqrt(20)` lies strictly between 4 and 5 and is irrational, making it a suitable example of an irrational number between 4 and 5.
Therefore, `4 < sqrt(20) < 5` and `sqrt(20)` is irrational.
