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Questions
Income of 100 students of their parents is given as follows:
| Income (in thousand Rs.) |
No. of students (f) |
| 0 – 8 | 8 |
| 8 – 16 | 35 |
| 16 – 24 | 35 |
| 24 – 32 | 14 |
| 32 – 40 | 8 |
Draw an ogive for the given distribution on a graph sheet. Use a suitable scale for your exercise. Use your ogive to estimate:
- the median income.
- Calculate the income below which freeship will be awarded to students if their parents income is in the bottom 15%
- Mean income.
The incomes of the parents of 100 students in a class in a certain university are tabulated below.
| Income (in thousand ₹) |
0 – 8 | 8 – 16 | 16 – 24 | 24 – 32 | 32 – 40 |
| No. of students | 8 | 35 | 35 | 14 | 8 |
- Draw a cumulative frequency curve to estimate the median income.
- If 15% of the students are given freeships on the basis of the income of their parents, find the annual income of parents, below which the freeships will be awarded.
- Calculate the Arithmetic mean.
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Solution
i. Cumulative frequency curve
| Income (in thousand Rs.) |
No. of students (f) |
Cumulative Frequency |
Class Mark x |
fx |
| 0 – 8 | 8 | 8 | 4 | 32 |
| 8 – 16 | 35 | 43 | 12 | 420 |
| 16 – 24 | 35 | 78 | 20 | 700 |
| 24 – 32 | 14 | 92 | 28 | 392 |
| 32 – 40 | 8 | 100 | 36 | 288 |
| `sumf = 100` | `sumfx = 1832` |
We plot the points (8, 8), (16, 43), (24, 78), (32, 92) and (40, 100) to get the curve as follows:

Here, N = 100
`=> N/2 = 50`
At y = 50, affix A.
Through A, draw a horizontal line meeting the curve at B.
Through B, a vertical line is drawn which meets OX at M.
OM = 17.6 units
Hence, median income = 17.6 thousands
ii. 15% of 100 student = `(15 xx 100)/100 = 15`
From c.f. 15, draw a horizontal line which intersects the curve at P.
From P, draw a perpendicular to x-axis meeting it at Q which is equal to 9.6.
Therefore, freeship will be awarded to students provided annual income of their parents is upto 9.6 thousands.
iii. Mean = `(sumfx)/(sumf) = 1832/100 = 18.32`
