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Question
In which of the following pairs, the two species have identical bond order?
Options
\[\ce{N^{-}_2, O^{2-}_2}\]
\[\ce{N^{-}_2, O^{-}_2}\]
\[\ce{N^{-}_2, O^{+}_2}\]
\[\ce{O^{+}_2, N^{2-}_2}\]
MCQ
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Solution
\[\ce{N^{-}_2, O^{+}_2}\]
Explanation:
Total amount of electrons in \[\ce{N^{-}_2}\] = 7 + 7 + 1 = 15
Total amount of electrons in \[\ce{N^{2-}_2}\] = 7 + 7 + 2 = 16
Total amount of electrons in \[\ce{O^{2-}_2}\] = 8 + 8 + 2 = 18
Total amount of electrons in \[\ce{O^{-}_2}\] = 8 + 8 + 1 = 17
Total amount of electrons in \[\ce{O^{+}_2}\] = 8 + 8 – 1 = 15
The configuration will be the same since \[\ce{N^{-}_2}\] and \[\ce{O^{+}_2}\] contain the same total amount of electrons. As a result, \[\ce{N^{-}_2}\] and \[\ce{O^{+}_2}\] have the same bond order.
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Bond Parameters - Bond Order
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