Question

In which of the following compounds, an element exhibits two different oxidation states.

Options

• \[\ce{NH2OH}\]

• \[\ce{NH4NO3}\]

• \[\ce{N2H4}\]

• \[\ce{N3H}\]

Answer 1

\[\ce{NH4NO3}\]

Explanation:

The oxidation states are given below:

In \[\ce{NH2OH}\] oxidation of N is – 1.

\[\ce{NH4NO3}\] exists as \[\ce{NH^{+}4 . NO^{-}3}\],

Thus, the oxidation state of N in \[\ce{NH^{+}4}\] is – 3 while in \[\ce{NO^{-}3}\] is + 5.

In \[\ce{N2H4}\] oxidation of N is – 2

In \[\ce{N2H}\] oxidation of N is `(-1)/3`.