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Question
In the rectangle ABCD, the diagonals intersect at O. If ∠COD = 120° and AB = 6 cm, OP is perpendicular to AB. Find x, y, BC and AC.

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Solution
Given:
Rectangle ABCD, with diagonals intersecting at O.
∠COD = 120°
AB = 6 cm → implies AP = PB = 3 cm (since diagonals bisect each other).
OP ⊥ AB.
Required: Find values of x, y, BC, and AC.
Step 1: Understand Triangle AOP
In triangle AOP:
- Right-angled at P
- ∠AOP = 60°
- AP = 1 cm
Step 2: Use trigonometry to find x = OP
We use:
tan(60∘) = `"opposite"/"adjacent" = (OP)/(AP)`
Substitute:
tan(60∘) = `sqrt3
`x/1 = sqrt3`
= `x = sqrt3` cm
Step 3: Use trigonometry to find y = AO
We use:
sin(60∘) = `"opposite"/"hypotenuse" = x/y`
Substitute:
`sqrt3/2 = sqrt3/y`
y = 2
y = `2 sqrt3` cm
Step 4: Find BC
In a rectangle:
Opposite sides are equal
BC = AD
AD = 2x = 2 · `sqrt3 = 2 sqrt3`
Step 5: Find diagonal AC
In a rectangle:
Diagonal are equal
AO = `2sqrt3 = AC = 2 * AO = 4sqrt3` cm
