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Question
In the given figure, the centre O of the small circle lies on the circumference of the bigger circle. If ∠APB = 75° and ∠BCD = 40°, find : ∠ABD
Sum
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Solution
Join AB and AD
In cyclic quadrilateral ABDC
∠ABD = 180° - ∠ACD = 180° - (40° + 30° ) = 110°
(pair of opposite angles in a cyclic quadrilateral are supplementary)
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