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Question
In the given figure BD = BC, find the value of x
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Solution
Given that BD = BC
∆BDC is on isosceles triangle.
In isosceles triangle, angles opposite to equal sides are equal.
∠BDC = ∠BCD ...(1)
Also ∠BCD + ∠BCX = 180° ...[∵ Liner Pair]
∠BCD + 115° = 180°
∠BCD = 180° – 115°
∠BCD = 65° ...[By (1)]
In ∆ADB
∠BAD + ∠ADB = ∠BDC ...[∵ BDC is the exterior angle and ∠BAD and ∠ABD are interior opposite angles]
35° + x = 65°
x = 65° – 35°
x = 30°
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