Question

In the given figure, AC is the diameter of circle, centre O. CD and BE are parallel. Angle AOB = 80^o and angle ACE = 10^o. Calculate: Angle CED.

Answer 1

∠BED =180° - ∠BCD =180° -100° = 80°

(pair of opposite angles in a cyclic quadrilateral are supplementary)

⇒∠CED + 50° = 80°

⇒ ∠CED = 30°