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Question
In the given figure, AB = BC = CD and ∠ABC = 132° . Calcualte: ∠ COD.
Sum
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Solution
In the figure, O is the centre of circle, with AB = BC = CD.
Also, ∠ABC = 132°
Arc CD subtends ∠COD at the centre and
∠CED at the remaining part of the circle.
∴ COD = 2∠CED
= 2 × 24°
= 48°
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