Question

In the given circuit determine the value of:

1. Total resistance of the circuit
2. Current flowing through the ammeter.

Answer 1

(i) The resistance 10 Ω and 50 Ω are connected in series, so their equivalent resistance is:

R_s = 10 + 50 = 60 Ω

Now R_s and 30 Ω are connected in parallel, so their equivalent resistance is:

`1/("R"_"total") = 1/60 + 1/30`

`1/("R"_"total") = 3/60`

`60 xx 1 = 3 xx "R"_"total"`

`60 = 3 xx "R"_"total"`

`60/3 = "R"_"total"`

R_total = 20 Ω

Hence, total resistance of the circuit is 20 Ω.

(ii) Given, V = 6 V

Current flowing through the ammeter, 

I = `"V"/"R"`

Or, I = `6/20` or `3/10` = 0.3 A

Thus, the current flowing through the ammeter is 0.3 A.