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In the following nuclear reaction, αβαγD→αDA1→βA−DA2→αDA3→γDA4. The mass number of D is 182 and its atomic number is 74. The mass number and atomic number of D4 respectively will be ______.

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Question

In the following nuclear reaction, \[\ce{D->[α]D_1->[β^-]D_2->[α]D_3->[γ]D_4}\]. The mass number of D is 182 and its atomic number is 74. The mass number and atomic number of D4 respectively will be ______.

Options

  • 174 and 71

  • 174 and 69

  • 172 and 69

  • 172 and 71

MCQ
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Solution

In the following nuclear reaction, \[\ce{D->[α]D_1->[β^-]D_2->[α]D_3->[γ]D_4}\]. The mass number of D is 182 and its atomic number is 74. The mass number and atomic number of D4 respectively will be 174 and 71.

Explanation:

We can write the given reaction as,

D = D4 + 2α + β + γ

Hence, D4 = D – 2α – β – γ

So, the atomic number of D4 = atomic number of D – 2 × 2 + 1.

= 74 – 4 + 1

= 71

Similarly, mass number of D4 = Mass number of D – 2 × 4

= 182 – 8

= 174

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Mass-Energy Equivalence and Nuclear Reactions
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