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Question
In the following figure, l || m || n and AB = BC, find:
- PQ if QR = 4 cm
- BO if CR = 6 cm

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Solution
Given:
Lines l || m || n. Points A, B, C lie on one transversal top, middle, bottom respectively and P, Q, R lie on the other transversal top, middle, bottom respectively.
AB = BC.
- QR = 4 cm.
- CR = 6 cm.
i. Find PQ when QR = 4 cm
Step-wise calculation:
1. AB = BC ⇒ B is the midpoint of AC.
By the midpoint/intercept theorem for three parallel lines, the corresponding segment on the other transversal is also bisected.
So, Q is the midpoint of PR.
Hence, PQ = QR.
2. Given QR = 4 cm
And PQ = QR
⇒ PQ = 4 cm
ii. Find BO when CR = 6 cm
Step-wise calculation:
1. Put coordinates or use linear interpolation along the line AR:
For the line joining A (on l) and R (on n), the point on m height halfway between l and n has x-coordinate `xO = (xA + xR)/2`.
Likewise, for the line joining A and C, the middle point B on m has `xB = (xA + xC)/2`.
This is the same midpoint/intercept idea on parallel lines.
2. BO = |xO – xB|
= `|(xA + xR)/2 - (xA + xC)/2|`
= `|(xR - xC)|/2`
3. But |xR – xC| is the horizontal distance CR on the bottom line.
So, `BO = (CR)/2`.
4. Given CR = 6 cm
⇒ `BO = 6/2`
⇒ BO = 3 cm
