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Question
In the figure, ∠DBC = 58°. BD is a diameter of the circle. Calculate : ∠BAC
Sum
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Solution
In cyclic quadrialteral ABEC,
∠BAC + ∠BEC = 180°
⇒ ∠BAC + 148° = 180°
⇒ ∠BAC = 180° - 148°
⇒ ∠BAC = 32°
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