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In the expression P = E l2 m–5 G–2, E, m, l and G denote energy, mass, angular momentum and gravitational constant, respectively. Show that P is a dimensionless quantity. - Physics

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Question

In the expression P = E l2 m–5 G–2, E, m, l and G denote energy, mass, angular momentum and gravitational constant, respectively. Show that P is a dimensionless quantity.

Long Answer
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Solution

Dimensional formulas of E, l and G:

E = [ML2T–2]

l = [ML2T–1]

G = [M–1L3T–2]

∴ Dimension of P = El2m–5G–2:

[P] = `([E] [l^2])/([M^5][G^2])`

= `([ML^2T^-2] [ML^2T^-1]^2)/([M]^5[M^-1L^3T^-2]^2`

= `[M^0L^0T^0]`

So, P is a dimensionless quantity.

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Chapter 2: Units and Measurements - Exercises [Page 11]

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NCERT Exemplar Physics [English] Class 11
Chapter 2 Units and Measurements
Exercises | Q 2.39 | Page 11

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