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Question
In the expression \[A=\frac{xy^{3}}{z^{2}}\] the percentage error is given by ______.
Options
\[\left(\frac{\Delta\mathrm{x}}{\mathrm{x}}+3\frac{\Delta\mathrm{y}}{\mathrm{y}}-2\frac{\Delta\mathrm{z}}{\mathrm{z}}\right)\times100\%\]
\[\left(\frac{\Delta\mathrm{x}}{\mathrm{x}}+\frac{3\Delta\mathrm{y}}{\mathrm{y}}+\frac{2\Delta\mathrm{z}}{\mathrm{z}}\right)\times100\%\]
\[\left(\frac{\Delta\mathbf{x}}{\mathbf{x}}-\frac{3\Delta\mathbf{y}}{\mathbf{y}}-\frac{2\Delta\mathbf{z}}{\mathbf{z}}\right)\times100\%\]
\[\left(\frac{\Delta x}{x}-3\frac{\Delta y}{y}+2\frac{\Delta z}{z}\right)\times100\%\]
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Solution
In the expression \[A=\frac{xy^{3}}{z^{2}}\] the percentage error is given by \[\left(\frac{\Delta\mathrm{x}}{\mathrm{x}}+\frac{3\Delta\mathrm{y}}{\mathrm{y}}+\frac{2\Delta\mathrm{z}}{\mathrm{z}}\right)\times100\%\].
Explanation:
For \[A=\frac{xy^3}{z^2}\]:
- Error in multiplication/division → add relative errors
- Powers become coefficients
So:
- \[x\to\frac{\Delta x}{x}\]
- \[y^3\to3\frac{\Delta y}{y}\]
- \[z^2\to2\frac{\Delta z}{z}\]
All are added to get total percentage error.
