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Maharashtra State BoardSSC (English Medium) 8th Standard

In the example given below, the radius of the base of a cylinder and its height is given. Then find the curved surface area and total surface area. r = 4.2 cm, h = 14 cm - Mathematics

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Question

In the example given below, the radius of the base of a cylinder and its height is given. Then find the curved surface area and total surface area.

r = 4.2 cm, h = 14 cm

Sum
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Solution

We know that,

Curved surface area = 2πrh

Total surface area = 2πr(h + r)

Here, r = 4.2 cm, h = 14 cm

Curved surface area of a cylinder = 2πrh

= `2 xx 22/7 xx 4.2 xx 14`

= `44 xx 8.4`

= 369.6 sq.cm.

Total surface area of a cylinder = 2πr(h + r)

= `2 xx 22/7 xx 4.2(14 + 4.2)`

= `44 xx 0.6 xx 18.2`

= `26.4 xx 18.2`

= 480.48 sq.cm.

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Chapter 16: Surface area and Volume - Practice Set 16.2 [Page 110]

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Balbharati Mathematics [English] Standard 8 Maharashtra State Board
Chapter 16 Surface area and Volume
Practice Set 16.2 | Q 1. (5) | Page 110
Balbharati Mathematics Integrated [English] Standard 8 Maharashtra State Board
Chapter 16 Surface Area and Volume
Practice Set 16.2 | Q 1. (5) | Page 65
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