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In the adjoining figure, BM = 2CM. If ar (ΔАBC) = 30 cm^2, then ar (ΔABM) is: - Mathematics

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Question

In the adjoining figure, BM = 2CM. If ar (ΔАBC) = 30 cm2, then ar (ΔABM) is:

Options

  • 20 cm2

  • 15 cm2

  • 10 cm2

  • 5 cm2

MCQ
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Solution

20 cm

Explanation:

Triangles ABM and ABC share the same altitude from A.

So, their areas are proportional to their bases on BC. 

Since BM : CM = 2 : 1.

BC = BM + CM = 3 parts.

So, `"area"(ABM) = (BM)/(BC) xx "area" (ABC)`

= `(2/3) xx 30`

= 20 cm2

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Chapter 13: Theorems on Area - Exercise 13B [Page 261]

APPEARS IN

Nootan Mathematics [English] Class 9 ICSE
Chapter 13 Theorems on Area
Exercise 13B | Q 10. | Page 261
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