Question

In quadrilateral ABCD, the diagonals AC and BD intersect each other at point O. If AO = 2CO and BO = 2DO; show that: OA × OD = OB × OC.

Answer 1

Since AO = 2CO and BO = 2DO,

`(AO)/(CO) = 2/1 = (BO)/(DO)`

So, OA × OD = OB × OC