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Maharashtra State BoardSSC (English Medium) 9th Standard

In ΔPQR, ∠Q = 90°, PQ = 12, QR = 5 and QS is a median. Find l(QS). - Geometry

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Question

In ΔPQR, ∠Q = 90°, PQ = 12, QR = 5 and QS is a median. Find l(QS).

Sum
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Solution

In △PQR, ∠Q = 90°      ...[Given]

△PQR is a right angle triangle.

∴ By Pythagoras theorem,

∴ PR2 = PQ2 + QR2          

⇒ PR= 122 + 52

⇒ PR= 144 + 25

⇒ PR= 169

⇒ PR = `sqrt169`

⇒ PR = 13   

In △PQR,

seg QS is the median on hypotenuse PR. 

∴ QS = `1/2`PR           ...[In a right angled triangle, the length of the median on the hypotenuse is half the length of the hypotenuse.]

∴ QS = `1/2 × 13`

∴ QS = 6.5 units 

Hence, the length of QS is 6.5 units.

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Chapter 3: Triangles - Practice Set 3.3 [Page 38]

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Balbharati Mathematics 2 [English] Standard 9 Maharashtra State Board
Chapter 3 Triangles
Practice Set 3.3 | Q 3. | Page 38

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