Advertisements
Advertisements
Question
In ΔPQR, ∠Q = 90°, PQ = 12, QR = 5 and QS is a median. Find l(QS).
Advertisements
Solution

In △PQR, ∠Q = 90° ...[Given]
△PQR is a right angle triangle.
∴ By Pythagoras theorem,
∴ PR2 = PQ2 + QR2
⇒ PR2 = 122 + 52
⇒ PR2 = 144 + 25
⇒ PR2 = 169
⇒ PR = `sqrt169`
⇒ PR = 13
In △PQR,
seg QS is the median on hypotenuse PR.
∴ QS = `1/2`PR ...[In a right angled triangle, the length of the median on the hypotenuse is half the length of the hypotenuse.]
∴ QS = `1/2 × 13`
∴ QS = 6.5 units
Hence, the length of QS is 6.5 units.
APPEARS IN
RELATED QUESTIONS
The length of hypotenuse of a right angled triangle is 15. Find the length of median of its hypotenuse.
In the given figure, if seg PR ≅ seg PQ, show that seg PS > seg PQ.

Draw an obtuse angled Δ STV. Draw its medians and show the centroid.
Draw an obtuse angled Δ LMN. Draw its altitudes and denote the orthocentre by ‘O’.
Draw an isosceles triangle. Draw all of its medians and altitudes. Write your observation about their points of concurrence.
The centroid of a triangle divides each medians in the ratio _______
In any triangle the centroid and the incentre are located inside the triangle
The centroid, orthocentre, and incentre of a triangle are collinear
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If DE = 44, then DM = ?
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If PD = 12, then PN = ?
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If DO = 8, then FD = ?
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If OE = 36 then EP = ?
In ∆ABC, AD is the bisector of ∠A meeting BC at D, CF ⊥ AB and E is the mid-point of AC. Then median of the triangle is ______.
If we join a vertex to a point on opposite side which divides that side in the ratio 1 : 1, then what is the special name of that line segment?
What is a median of a triangle?
In a triangle, where is the centroid always located?
