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Question
In photoelectric emission, a radiation whose frequency is 4 times threshold frequency of a certain metal is incident on the metal. Then the maximum possible velocity of the emitted electron will be
Options
`sqrt(("hv"_0)/"m")`
`sqrt((6"hv"_0)/"m")`
`2sqrt(("hv"_0)/"m")`
`sqrt(("hv"_0)/(2"m"))`
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Solution
`sqrt((6"hv"_0)/"m")`
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