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In the Following Reaction Between Lead Sulphide and Hydrogen Peroxide: Pbs (S) + 4h2o2(Aq) → Pbso4(S) + 4h2o(1) (A) Which Substance is Reduced? (B) Which Substance is Oxidised? - Science

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Question

In the following reaction between lead sulphide and hydrogen peroxide:

PbS (s) + 4H2O2(aq) → PbSO4(s) + 4H2O(1)

(a) which substance is reduced?
(b) Which substance is oxidised?

 

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Solution

(a) Hydrogen peroxide (H2O2) is reduced.

(b) Lead sulphide (PbS) is oxidised.
This is because lead sulphide gains oxygen, while hydrogen peroxide loses oxygen.

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Chapter 1: Chemical Reactions and Equations - Exercise 2 [Page 46]

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Lakhmir Singh Chemistry (Science) [English] Class 10
Chapter 1 Chemical Reactions and Equations
Exercise 2 | Q 21 | Page 46

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