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Question
In the following figure, OABC is a square of side 7 cm. If OAPC is a quadrant of a circle with centre O, then find the area of the shaded region. (Use π = 22/7)

Sum
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Solution
Area of shaded region = Area of square OABC − Area of quadrant OAPC
\[= \left( Side \right)^2 - \frac{1}{4}\pi r^2 \]
\[ = \left( 7 \right)^2 - \frac{1}{4} \times \frac{22}{7} \times 7 \times 7\]
\[ = 49 - 38 . 5\]
\[ = 10 . 5 {cm}^2\]
\[ = \left( 7 \right)^2 - \frac{1}{4} \times \frac{22}{7} \times 7 \times 7\]
\[ = 49 - 38 . 5\]
\[ = 10 . 5 {cm}^2\]
Hence, the area of the shaded region is 10.5 cm2
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