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Question
In Fig below we have AB || CD || EF. If AB = 6 cm, CD = x cm, EF = 10 cm, BD = 4 cm and DE = y cm, calculate the values of x and y.

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Solution
We have AB || CD || EF. If AB = 6 cm, CD = x cm, EF = 10 cm, BD = 4 cm and DE = y cm
In ΔECD and ΔEAB
∠CED = ∠AEB [common]
∠ECD = ∠EAB [corresponding angles]
Then, ΔECD ~ ΔEAB ….(i) [By AA similarity]
`therefore"EC"/"EA"="CD"/"AB"` [Corresponding parts of similar Δ are proportional]
`rArr"EC"/"EA"=x/6` .........(ii)
In ΔACD and ΔAEF
∠CAD = ∠EAF [common]
∠ACD = ∠AEF [corresponding angles]
Then, ΔACD ~ ΔAEF [By AA similarity]
`therefore"AC"/"AE"="CD"/"EF"`
`rArr"AC"/"AE"=x/10` ..........(iii)
Add equations (iii) & (ii)
`therefore"EC"/"EA"+"AC"/"AE"=x/6+x/10`
`rArr"AE"/"AE"=(5x+3x)/30`
`rArr1=(8x)/30`
`rArrx=30/8=3.75` cm
From (i) "DC"/"AB"="ED"/"BE"
`rArr3.75/6=y/(y+4)`
⇒ 6y = 3.75y + 15
⇒ 2.25y = 15
`rArry=15/2.25=6.67` cm
