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Question
In cyclic quadrilateral ABCD, ∠DAC = 27°; ∠DBA = 50° and ∠ADB = 33°. Calculate : ∠DCB.
Sum
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Solution
∠ACB = ∠ADB = 33°
∠ACD = ∠ABD = 50°
(Angles subtended by the same chord on the circle are equal)
∴ ∠DCB = ∠ACD + ∠ACB
= 50° + 33°
= 83°
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