Question

In case of dimensions of electric field and electric dipole moment the power of mass is respectively.

Options

• 1, 1

• 1, 0

• 0, 1

• 0, 0

Answer 1

1, 0

Explanation:

Electric field, E = `"F"/"q"`

Where, F = force and q = electric charge

Dimensions of E or [E] = `(["M L T"^-2])/(["A T"]) = ["ML T"^-3"A"^-1]`

Power of mass = 1

Electric dipole moment, m = I × A

where, I = current and A = area

Dimensions of m = (M] = [A L²] = [M⁰L²T⁰A]

Hence, power of mass = 0