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In acidic medium, H2O2 changes Cr⁢2⁢O⁢2−7 to CrO5 which has two (-O-O-) bonds. Oxidation state of Cr in CrO5 is ______. - Chemistry (Theory)

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Question

In acidic medium, H2O2 changes \[\ce{Cr2O^{2-}_7}\] to CrO5 which has two (-O-O-) bonds. Oxidation state of Cr in CrO5 is ______.

Options

  • +5

  • +3

  • +6

  • −10

MCQ
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Solution

In acidic medium, H2O2 changes \[\ce{Cr2O^{2-}_7}\] to CrO5 which has two (-O-O-) bonds. Oxidation state of Cr in CrO5 is +6.

Explanation:

The compound CrO5 is chromium pentoxide, also called chromium peroxide. It contains one Cr atom and 5 oxygen atoms. Out of the 5 oxygen atoms, 4 oxygen atoms are part of 2 peroxo groups (-O-O-), each contributing −1 oxidation state. The remaining 1 oxygen atom is a normal oxide (O2−) with −2 oxidation state. The oxidation state of Cr is:

x + 2(−1) + (−2) = 0

⇒ x − 4 = 0

⇒ x = +6

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