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Question
In ΔABC, AB = AC, BM and Cn are perpendiculars on AC and AB respectively. Prove that BM = CN.
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Solution
In ΔBNC and ΔCMB
∠BNC = ∠CMB = 90°
∠NBC = ∠MCB ...(AB = AC)
BC = BC
Therefore, ΔBNC ≅ ΔCMB ...(AAS criteria)
Hence, BM = CN.
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