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In a rectangular plot, 5 square flower beds of side (x + 2) metres each have been laid (see the figure). Find the total cost of fencing the flower beds at the cost of ₹ 50 per 100 metres:

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Question

In a rectangular plot, 5 square flower beds of side (x + 2) metres each have been laid (see the figure). Find the total cost of fencing the flower beds at the cost of ₹ 50 per 100 metres:

Sum
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Solution

Given, side of one square flower bed = (x + 2) m

 ∴ Perimeter of one square flower bed = 4(Side) = 4(x + 2) m

Now, total perimeter of 5 such square flower beds = 5 × Perimeter of one square

= 5 × 4(x + 2)

= 20(x + 2) m

∵ Cost of fencing of 100 m = ₹ 50

 ∴ Cost of 1 m = ₹ `50/100`

 ∴ Cost of 20(x + 2) m = `50/100 xx 20(x + 2)`

= 10(x + 2)

= ₹ (10x + 20)

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Chapter 10: Algebraic Expressions - Exercise [Page 325]

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NCERT Exemplar Mathematics Exemplar Class 7
Chapter 10 Algebraic Expressions
Exercise | Q 82. | Page 325

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