English
Tamil Nadu Board of Secondary EducationHSC Science Class 12

In a pack of 52 playing cards, two cards are drawn at random simultaneously. If the number of black cards drawn is a random variable, find the values of the random variable and number of points in its - Mathematics

Advertisements
Advertisements

Question

In a pack of 52 playing cards, two cards are drawn at random simultaneously. If the number of black cards drawn is a random variable, find the values of the random variable and number of points in its inverse images

Chart
Sum
Advertisements

Solution

Total number of playing cards = 52

Number of Black cards = 26

Number of Non-black or Red cards = 26

Let ‘X’ be the random variable denotes the number of black cards. Since two black cards are drawn, ’X’ takes the values 0, 1, 2

X(Non-black Cards) = X(26C1 × 25C1) = X(650) = 0

X(1 Black Card) = X(26C1 × 26C0) = X(26) = 1

X(2 Black Cards) = X(26C1 × 25C1) = X(650) = 2

Values of X 0 1 2 Total
Number of elements in inverse images 650 26 650 1326
shaalaa.com
Random Variable
  Is there an error in this question or solution?
Chapter 11: Probability Distributions - Exercise 11.1 [Page 184]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 11 Probability Distributions
Exercise 11.1 | Q 2 | Page 184

RELATED QUESTIONS

Suppose X is the number of tails occurred when three fair coins are tossed once simultaneously. Find the values of the random variable X and number of points in its inverse images


An urn contains 5 mangoes and 4 apples. Three fruits are taken at random. If the number of apples taken is a random variable, then find the values of the random variable and number of points in its inverse images


Choose the correct alternative:

Let X represent the difference between the number of heads and the number of tails obtained when a coin is tossed n times. Then the possible values of X are


The discrete random variable X has the probability function.

Value
of X = x
0 1 2 3 4 5 6 7
P(x) 0 k 2k 2k 3k k2 2k2 7k2 + k

Evaluate p(x < 6), p(x ≥ 6) and p(0 < x < 5)


The discrete random variable X has the probability function.

Value
of X = x
0 1 2 3 4 5 6 7
P(x) 0 k 2k 2k 3k k2 2k2 7k2 + k

If P(X ≤ x) > `1/2`, then find the minimum value of x.


Describe what is meant by a random variable


Explain the distribution function of a random variable


State the properties of distribution function.


Choose the correct alternative:

A formula or equation used to represent the probability distribution of a continuous random variable is called


Choose the correct alternative:

If c is a constant, then E(c) is


Choose the correct alternative:

If c is a constant in a continuous probability distribution, then p(x = c) is always equal to


Choose the correct alternative: 

If we have f(x) = 2x, 0 ≤ x ≤ 1, then f(x) is a


Choose the correct alternative: 

Which one is not an example of random experiment?


Choose the correct alternative: 

A set of numerical values assigned to a sample space is called


Choose the correct alternative: 

A variable which can assume finite or countably infinite number of values is known as


The probability function of a random variable X is given by
p(x) = `{{:(1/4",",  "for"  x = - 2),(1/4",",  "for"  x = 0),(1/2",",  "for"  x = 10),(0",",  "elsewhere"):}`
Evaluate the following probabilities
P(X ≤ 0)


The probability function of a random variable X is given by
p(x) = `{{:(1/4",",  "for"  x = - 2),(1/4",",  "for"  x = 0),(1/2",",  "for"  x = 10),(0",",  "elsewhere"):}`
Evaluate the following probabilities
P(X < 0)


The probability density function of a continuous random variable X is
f(x) = `{{:("a" + "b"x^2",",  0 ≤ x ≤ 1),(0",",  "otherwise"):}`
where a and b are some constants. Find a and b if E(X) = `3/5`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×