Question

In a hypothetical reaction,

\[\ce{2A + B -> Products}\]. Rate = k [A]² [B]

Molar concentration of 'B' is kept constant and molar concentration of 'A' is tripled, then the rate of reaction will ____________.

Options

• increase by 3 times

• increase by 6 times

• increase by 9 times

• decrease by 6 times

Answer 1

In a hypothetical reaction,

\[\ce{2A + B -> Products}\]. Rate = k [A]² [B]

Molar concentration of 'B' is kept constant and molar concentration of 'A' is tripled, then the rate of reaction will increase by 9 times.

Explanation:

Because rate = k [A]² [B], raising the concentration of [A] by three times increases the rate by nine times.