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Questions

If `y = x^tan x + sqrt(x^2 + 1)/2, "find"  (dy)/(dx) ?`

Find `(dy)/(dx), if y = x^tanx + sqrt(x^2 + 1)/2`.

Sum
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Solution

`y = x^tanx + sqrt(x^2 + 1)/2    ...(i)`

Let u = `x^tanx, v = sqrt(x^2 + 1)/2`

Equation (i) becomes

y = u + v

Differentiate w.r.t. x,

`(dy)/(dx) = (du)/(dx) + (dv)/(dx)`

Now, u = xtan x

taking log on both sides

log u = log (xtan x)

log u = tan x log x

Differentiate w.r.t. x,

`1/u (du)/(dx) = (tan x)/x + log x  sec2^2 x`

⇒ `(du)/(dx) = u[(tan x)/x  + log x  sec^2 x]`

⇒ `(du)/(dx) = x^tan x[(tan x)/x + log x  sec^2 x]`

Again take,

v = `sqrt(x^2 - 1)/2`

`(dv)/(dx) = 1/2 xx 1/(2sqrt(x^2 + 1)) xx (2x)`

= `x/(2sqrt(x^2 + 1)`

Put the value `(du)/(dx) and (dv)/(dx)  "in equation" (ii),`

Now, `(dy)/(dx) = x^tanx[tan x/x + log x  sec^2 x] + x/(2sqrt(x^2 + 1)`

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Chapter 11: Differentiation - Exercise 11.05 [Page 90]

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RD Sharma Mathematics [English] Class 12
Chapter 11 Differentiation
Exercise 11.05 | Q 60 | Page 90

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