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Question
If x+y=8, then the maximum value of xy is ____________ .
Options
8
16
20
24
MCQ
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Solution
\[16\]
\[\text { Given }: x + y = 8\]
\[ \Rightarrow y = 8 - x.........................\left( 1 \right)\]
\[\text { Let } f\left( x \right) \text { be } xy . \]
\[ \Rightarrow f\left( x \right) = x\left( 8 - x \right).....................\left[ \text { From eq } . \left( 1 \right) \right]\]
\[ \Rightarrow f'\left( x \right) = 8 - 2x\]
\[\text { For a local maxima or a local minima, we must have } \]
\[f'\left( x \right) = 0\]
\[ \Rightarrow 8 - 2x = 0\]
\[ \Rightarrow 8 = 2x\]
\[ \Rightarrow x = 4\]
\[ \Rightarrow y = 8 - 4 = 4..................\left[ \text { From eq.} \left( 1 \right) \right]\]
\[\text { Now,} \]
\[f''\left( x \right) = - 2\]
\[ \Rightarrow f''\left( 4 \right) = - 2 < 0\]
\[\text { So, x = 4 is a local maxima }. \]
\[\text { Hence, the local maximumvalue is given by }\]
\[f\left( 4 \right) = 4 \times 4 = 16\]
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