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# If x is a positive integer such that the distance between points P (x, 2) and Q (3, −6) is 10 units, then x = - Mathematics

MCQ

If x is a positive integer such that the distance between points P (x, 2) and Q (3, −6) is 10 units, then x =

#### Options

• 3

• -3

• 9

• -9

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#### Solution

It is given that distance between P (x, 2) and Q(3 , - 6 )  is 10.

In general, the distance between A(x1 , y 1 )   and B (x2 , y2) is given by,

AB^2 = ( x_2-x_1)^2 + (y_2 - y_1)^2

So,

10^2 = (x - 3)^2 + (2 + 6)^2

On further simplification,

(x - 3)^2 = 36

 x = 3 +- 6

= 9 - 3

We will neglect the negative value. So,

x = 9

Is there an error in this question or solution?
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#### APPEARS IN

RD Sharma Class 10 Maths
Chapter 6 Co-Ordinate Geometry
Q 3 | Page 63
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