Question

If x = `"a"("t" - 1/"t")`, y = `"a"("t" + 1/"t")`, where t be the parameter, then `("d"y)/("d"x)` = ?

Options

• `x/y`

• `(-x)/y`

• `y/x`

• `(-y)/x`

Answer 1

`bb(x/y)`