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Question
If `vec(AB)=hatj+hatk` and `vec(AC)=3hati-hatj+4hatk` represent the two vectors along the sides AB and AC of ΔABC, prove that the median `vec(AD)=(vec(AB)+vec(AC))/2`, where D is midpoint of BC. Hence, find the length of median AD.
Sum
Theorem
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Solution
`veca=0`
`vecb= vec(AB)`
`vecc=vec(AC)`
`vecd=(vecb+vecc)/2`
= `(hatj+hatk+3hati-hatj+4hatk)/2`
= `(3hati)/2+(5hatk)/2`
`vecAD=vecd-veca`
`3/2hati+5/2hatk`
`|vecAD|=sqrt((3/2)^2+(5/2)^2)`
= `sqrt(9/4+25/4)`
= `sqrt(34/4)`
= `sqrt34/2`
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