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Question
If two circular rings A and B are of same mass but of radii r and 2r respectively, then the moment of inertia about an axis passing through C.G. and perpendicular to its plane, of A is ______.
Options
same as that of B
twice that of B
four times that of B
`1/4` that of B
MCQ
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Solution
If two circular rings A and B are of same mass but of radii r and 2r respectively, then the moment of inertia about an axis passing through C.G. and perpendicular to its plane, of A is `bbunderline(1/4 "that of B")`.
Explanation:
For ring A:
Radius = r
IA = Mr2 ...(i)
For ring B:
Radius = 2r
IB = M(2r)2 ...(ii)
Equations (i) and (ii) we get,
`(Mr^2)/(M(2r)^2) = (I_A)/(I_B)`
`(I_A)/(I_B) = 1/4`
`I_A = (I_B)/4`
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