Question

If the solubility product K_sp of a sparingly soluble salt AgBr at 25°C is x, the solubility of the salt is ____________.

Options

• `root2"x"`

• `root3"x"`

• `root3("x"/4)`

• `root2("x"/2)`

Answer 1

If the solubility product K_sp of a sparingly soluble salt AgBr at 25°C is x, the solubility of the salt is `underline(root2"x")`.

Explanation:

For \[\ce{AgBr ⇌ Ag^+ + Br^-}\]

x = 1, y = 1

K_sp = x^x × y^y × S^x+y

= 1¹ × 1¹ × S¹⁺¹

K_sp = S²

x = S²

S = `root2"x"` mol dm⁻³