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Question
If the sides of a cubic box are increased by 1, 2, 3 units respectively to form a cuboid, then the volume is increased by 52 cubic units. Find the volume of the cuboid
Sum
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Solution
Let the side of the cube be ‘x’
Sides of cuboid are (x + 1)(x + 2)(x + 3)
∴ Volume of cuboid = x3 + 52
⇒ (x + 1)(x + 2)(x + 3) = x3 + 52
⇒ (x2 + 3x + 2)(x + 3) = x3 + 52
⇒ x3 + 3x2 + 3x2 + 9x + 2x + 6 – x3 – 52 = 0
⇒ 6x2 + 11x – 46 = 0 ......(÷2)
⇒ (x – 2)(6x + 23) = 0
⇒ x – 2 = 0 or 6x + 23 = 0
⇒ x = 2 or x = `- 23/6` ......(not possible)
∴ x = 2
Volume of cube = 23 = 8
Volume of cuboid = 52 + 8 = 60 cubic units
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Basics of Polynomial Equations
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