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Question
If the mid-point of the line segment joining the points A(3, 4) and B(k, 6) is P(x, y) and x + y – 10 = 0, find the value of k.
Sum
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Solution 1
x + y − 10 = 0
Midpoint = `((x_1 + x_2)/2, (y_1+y_2)/2)`
`(x, y) = ((3 + k)/2, 10/2)`
`(x, y) = ((3 + k)/2, 5)`
`(3 + k)/2 + 5 - 10 = 0`
`(3 + k)/2 = 5`
3 + k = 10
k = 10 – 3
k = 7
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Solution 2
Here, `(3 + k)/2 = x`
And `y = (4 + 6)/2` = `10/2` = 5
Given, x + y – 10 = 0
⇒ `(3 + k)/2 + 5 - 10 = 0`
⇒ `(3 + k)/2 = 5`
⇒ 3 + k = 10
⇒ k = 10 – 3
⇒ k = 7
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