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Question
If the mean of the following distribution is 6, find the value of p.
| xi | 2 | 4 | 6 | 10 | p + 5 |
| fi | 3 | 2 | 3 | 1 | 2 |
Sum
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Solution
Step 1: Organize the data
Based on the table provided, let’s calculate the products of the values (xi) and their frequencies (fi):
| xi | fi | fi × xi |
| 2 | 3 | 2 × 3 = 6 |
| 4 | 2 | 4 × 2 = 8 |
| 6 | 3 | 6 × 3 = 18 |
| 10 | 1 | 10 × 1 = 10 |
| p + 5 | 2 | 2(p + 5) = 2p + 10 |
| Total | Σfi = 11 | Σ(fi × xi) = 52 + 2p |
Step 2: Set up the equation
We are given that the mean `(barx)` is 6. Plugging the totals from our table into the mean formula:
`6 = (52 + 2p)/11`
Step 3: Solve for p
1. Multiply both sides by 11 to clear the fraction:
66 = 52 + 2p
2. Subtract 52 from both sides:
66 – 52 = 2p
14 = 2p
3. Divide by 2:
p = 7
The value of p is 7.
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